Optimal. Leaf size=162 \[ \frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2+a^3 x \tanh ^{-1}(a x)-a^2 \text {Li}_3\left (1-\frac {2}{1-a x}\right )+a^2 \text {Li}_3\left (\frac {2}{1-a x}-1\right )+2 a^2 \text {Li}_2\left (1-\frac {2}{1-a x}\right ) \tanh ^{-1}(a x)-2 a^2 \text {Li}_2\left (\frac {2}{1-a x}-1\right ) \tanh ^{-1}(a x)+a^2 \log (x)-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )-\frac {\tanh ^{-1}(a x)^2}{2 x^2}-\frac {a \tanh ^{-1}(a x)}{x} \]
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Rubi [A] time = 0.46, antiderivative size = 162, normalized size of antiderivative = 1.00, number of steps used = 21, number of rules used = 15, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.682, Rules used = {6012, 5916, 5982, 266, 36, 29, 31, 5948, 5914, 6052, 6058, 6610, 5980, 5910, 260} \[ -a^2 \text {PolyLog}\left (3,1-\frac {2}{1-a x}\right )+a^2 \text {PolyLog}\left (3,\frac {2}{1-a x}-1\right )+2 a^2 \tanh ^{-1}(a x) \text {PolyLog}\left (2,1-\frac {2}{1-a x}\right )-2 a^2 \tanh ^{-1}(a x) \text {PolyLog}\left (2,\frac {2}{1-a x}-1\right )+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2+a^2 \log (x)+a^3 x \tanh ^{-1}(a x)-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )-\frac {\tanh ^{-1}(a x)^2}{2 x^2}-\frac {a \tanh ^{-1}(a x)}{x} \]
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 260
Rule 266
Rule 5910
Rule 5914
Rule 5916
Rule 5948
Rule 5980
Rule 5982
Rule 6012
Rule 6052
Rule 6058
Rule 6610
Rubi steps
\begin {align*} \int \frac {\left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{x^3} \, dx &=\int \left (\frac {\tanh ^{-1}(a x)^2}{x^3}-\frac {2 a^2 \tanh ^{-1}(a x)^2}{x}+a^4 x \tanh ^{-1}(a x)^2\right ) \, dx\\ &=-\left (\left (2 a^2\right ) \int \frac {\tanh ^{-1}(a x)^2}{x} \, dx\right )+a^4 \int x \tanh ^{-1}(a x)^2 \, dx+\int \frac {\tanh ^{-1}(a x)^2}{x^3} \, dx\\ &=-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+a \int \frac {\tanh ^{-1}(a x)}{x^2 \left (1-a^2 x^2\right )} \, dx+\left (8 a^3\right ) \int \frac {\tanh ^{-1}(a x) \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx-a^5 \int \frac {x^2 \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx\\ &=-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+a \int \frac {\tanh ^{-1}(a x)}{x^2} \, dx+a^3 \int \tanh ^{-1}(a x) \, dx-\left (4 a^3\right ) \int \frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx+\left (4 a^3\right ) \int \frac {\tanh ^{-1}(a x) \log \left (2-\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac {a \tanh ^{-1}(a x)}{x}+a^3 x \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )-2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1-a x}\right )+a^2 \int \frac {1}{x \left (1-a^2 x^2\right )} \, dx-\left (2 a^3\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx+\left (2 a^3\right ) \int \frac {\text {Li}_2\left (-1+\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx-a^4 \int \frac {x}{1-a^2 x^2} \, dx\\ &=-\frac {a \tanh ^{-1}(a x)}{x}+a^3 x \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+\frac {1}{2} a^2 \log \left (1-a^2 x^2\right )+2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )-2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1-a x}\right )-a^2 \text {Li}_3\left (1-\frac {2}{1-a x}\right )+a^2 \text {Li}_3\left (-1+\frac {2}{1-a x}\right )+\frac {1}{2} a^2 \operatorname {Subst}\left (\int \frac {1}{x \left (1-a^2 x\right )} \, dx,x,x^2\right )\\ &=-\frac {a \tanh ^{-1}(a x)}{x}+a^3 x \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+\frac {1}{2} a^2 \log \left (1-a^2 x^2\right )+2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )-2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1-a x}\right )-a^2 \text {Li}_3\left (1-\frac {2}{1-a x}\right )+a^2 \text {Li}_3\left (-1+\frac {2}{1-a x}\right )+\frac {1}{2} a^2 \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )+\frac {1}{2} a^4 \operatorname {Subst}\left (\int \frac {1}{1-a^2 x} \, dx,x,x^2\right )\\ &=-\frac {a \tanh ^{-1}(a x)}{x}+a^3 x \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)^2}{2 x^2}+\frac {1}{2} a^4 x^2 \tanh ^{-1}(a x)^2-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )+a^2 \log (x)+2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )-2 a^2 \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1-a x}\right )-a^2 \text {Li}_3\left (1-\frac {2}{1-a x}\right )+a^2 \text {Li}_3\left (-1+\frac {2}{1-a x}\right )\\ \end {align*}
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Mathematica [A] time = 0.07, size = 183, normalized size = 1.13 \[ a^3 x \tanh ^{-1}(a x)+a^2 \text {Li}_3\left (\frac {-a x-1}{a x-1}\right )-a^2 \text {Li}_3\left (\frac {a x+1}{a x-1}\right )-2 a^2 \text {Li}_2\left (\frac {-a x-1}{a x-1}\right ) \tanh ^{-1}(a x)+2 a^2 \text {Li}_2\left (\frac {a x+1}{a x-1}\right ) \tanh ^{-1}(a x)+\frac {1}{2} a^2 \left (a^2 x^2-1\right ) \tanh ^{-1}(a x)^2+\frac {\left (a^2 x^2-1\right ) \tanh ^{-1}(a x)^2}{2 x^2}+a^2 \log (x)-4 a^2 \tanh ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac {2}{1-a x}\right )-\frac {a \tanh ^{-1}(a x)}{x} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \operatorname {artanh}\left (a x\right )^{2}}{x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (a^{2} x^{2} - 1\right )}^{2} \operatorname {artanh}\left (a x\right )^{2}}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 1.88, size = 774, normalized size = 4.78 \[ 4 a^{2} \polylog \left (3, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-a^{2} \polylog \left (3, -\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}\right )-a^{2} \ln \left (1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}\right )+a^{2} \ln \left (1+\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+a^{2} \ln \left (\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}-1\right )-2 a^{2} \arctanh \left (a x \right )^{2} \ln \left (a x \right )+2 a^{2} \arctanh \left (a x \right )^{2} \ln \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )-2 a^{2} \arctanh \left (a x \right )^{2} \ln \left (1+\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-2 a^{2} \arctanh \left (a x \right )^{2} \ln \left (1-\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-4 a^{2} \arctanh \left (a x \right ) \polylog \left (2, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-4 a^{2} \arctanh \left (a x \right ) \polylog \left (2, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+2 a^{2} \arctanh \left (a x \right ) \polylog \left (2, -\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}\right )-i a^{2} \arctanh \left (a x \right )^{2} \pi \mathrm {csgn}\left (\frac {i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right )^{3}-\frac {a \arctanh \left (a x \right )}{x}+i a^{2} \pi \arctanh \left (a x \right )^{2} \mathrm {csgn}\left (i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )\right ) \mathrm {csgn}\left (\frac {i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right )^{2}+i a^{2} \pi \,\mathrm {csgn}\left (\frac {i}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right ) \mathrm {csgn}\left (\frac {i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right )^{2} \arctanh \left (a x \right )^{2}+4 a^{2} \polylog \left (3, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-i a^{2} \pi \,\mathrm {csgn}\left (i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )\right ) \mathrm {csgn}\left (\frac {i}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right ) \mathrm {csgn}\left (\frac {i \left (\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}-1\right )}{1+\frac {\left (a x +1\right )^{2}}{-a^{2} x^{2}+1}}\right ) \arctanh \left (a x \right )^{2}+a^{3} x \arctanh \left (a x \right )+\frac {a^{4} x^{2} \arctanh \left (a x \right )^{2}}{2}-\frac {\arctanh \left (a x \right )^{2}}{2 x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{16} \, {\left (2 \, x^{2} \log \left (-a x + 1\right ) - a {\left (\frac {a x^{2} + 2 \, x}{a^{2}} + \frac {2 \, \log \left (a x - 1\right )}{a^{3}}\right )}\right )} a^{4} - \frac {1}{2} \, a^{4} \int x \log \left (a x + 1\right ) \log \left (-a x + 1\right )\,{d x} + \frac {1}{4} \, a^{3} \int a x \log \left (a x + 1\right )^{2}\,{d x} + \frac {1}{4} \, a^{3} \int \frac {\log \left (a x + 1\right )^{2}}{a^{3} x^{3}}\,{d x} + \frac {1}{4} \, {\left (a x - {\left (a x - 1\right )} \log \left (-a x + 1\right ) - 1\right )} a^{2} - \frac {1}{2} \, a^{2} \int \frac {\log \left (a x + 1\right )^{2}}{x}\,{d x} + a^{2} \int \frac {\log \left (a x + 1\right ) \log \left (-a x + 1\right )}{x}\,{d x} - \frac {1}{4} \, a^{2} \int \frac {\log \left (-a x + 1\right )}{x}\,{d x} - \frac {1}{4} \, {\left (a {\left (\log \left (a x - 1\right ) - \log \relax (x)\right )} - \frac {\log \left (-a x + 1\right )}{x}\right )} a + \frac {{\left (a^{4} x^{4} - 1\right )} \log \left (-a x + 1\right )^{2}}{8 \, x^{2}} - \frac {1}{2} \, \int \frac {\log \left (a x + 1\right ) \log \left (-a x + 1\right )}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {atanh}\left (a\,x\right )}^2\,{\left (a^2\,x^2-1\right )}^2}{x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a x - 1\right )^{2} \left (a x + 1\right )^{2} \operatorname {atanh}^{2}{\left (a x \right )}}{x^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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